28p^2-36p+8=0

Solution for 28p^2-36p+8=0 equation:

28p^2-36p+8=0

a = 28; b = -36; c = +8;
Δ = b2-4ac
Δ = -362-4·28·8
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-20}{2*28}=\frac{16}{56}
=2/7
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+20}{2*28}=\frac{56}{56}
=1
$